3.306 \(\int \sqrt [3]{b \sin (e+f x)} \, dx\)

Optimal. Leaf size=58 \[ \frac {3 \cos (e+f x) (b \sin (e+f x))^{4/3} \, _2F_1\left (\frac {1}{2},\frac {2}{3};\frac {5}{3};\sin ^2(e+f x)\right )}{4 b f \sqrt {\cos ^2(e+f x)}} \]

[Out]

3/4*cos(f*x+e)*hypergeom([1/2, 2/3],[5/3],sin(f*x+e)^2)*(b*sin(f*x+e))^(4/3)/b/f/(cos(f*x+e)^2)^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2643} \[ \frac {3 \cos (e+f x) (b \sin (e+f x))^{4/3} \, _2F_1\left (\frac {1}{2},\frac {2}{3};\frac {5}{3};\sin ^2(e+f x)\right )}{4 b f \sqrt {\cos ^2(e+f x)}} \]

Antiderivative was successfully verified.

[In]

Int[(b*Sin[e + f*x])^(1/3),x]

[Out]

(3*Cos[e + f*x]*Hypergeometric2F1[1/2, 2/3, 5/3, Sin[e + f*x]^2]*(b*Sin[e + f*x])^(4/3))/(4*b*f*Sqrt[Cos[e + f
*x]^2])

Rule 2643

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1)*Hypergeomet
ric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2])/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]), x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin {align*} \int \sqrt [3]{b \sin (e+f x)} \, dx &=\frac {3 \cos (e+f x) \, _2F_1\left (\frac {1}{2},\frac {2}{3};\frac {5}{3};\sin ^2(e+f x)\right ) (b \sin (e+f x))^{4/3}}{4 b f \sqrt {\cos ^2(e+f x)}}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 55, normalized size = 0.95 \[ \frac {3 \sqrt {\cos ^2(e+f x)} \tan (e+f x) \sqrt [3]{b \sin (e+f x)} \, _2F_1\left (\frac {1}{2},\frac {2}{3};\frac {5}{3};\sin ^2(e+f x)\right )}{4 f} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*Sin[e + f*x])^(1/3),x]

[Out]

(3*Sqrt[Cos[e + f*x]^2]*Hypergeometric2F1[1/2, 2/3, 5/3, Sin[e + f*x]^2]*(b*Sin[e + f*x])^(1/3)*Tan[e + f*x])/
(4*f)

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fricas [F]  time = 0.49, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\left (b \sin \left (f x + e\right )\right )^{\frac {1}{3}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sin(f*x+e))^(1/3),x, algorithm="fricas")

[Out]

integral((b*sin(f*x + e))^(1/3), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (b \sin \left (f x + e\right )\right )^{\frac {1}{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sin(f*x+e))^(1/3),x, algorithm="giac")

[Out]

integrate((b*sin(f*x + e))^(1/3), x)

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maple [F]  time = 0.10, size = 0, normalized size = 0.00 \[ \int \left (b \sin \left (f x +e \right )\right )^{\frac {1}{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*sin(f*x+e))^(1/3),x)

[Out]

int((b*sin(f*x+e))^(1/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (b \sin \left (f x + e\right )\right )^{\frac {1}{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sin(f*x+e))^(1/3),x, algorithm="maxima")

[Out]

integrate((b*sin(f*x + e))^(1/3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int {\left (b\,\sin \left (e+f\,x\right )\right )}^{1/3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*sin(e + f*x))^(1/3),x)

[Out]

int((b*sin(e + f*x))^(1/3), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt [3]{b \sin {\left (e + f x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sin(f*x+e))**(1/3),x)

[Out]

Integral((b*sin(e + f*x))**(1/3), x)

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